Jawabanmu

2013-12-09T23:18:40+07:00
Mungkin begini maksudnya
y^{2} =  \frac{1}{x}+\frac{2}{x^{2}}+\frac{3}{x^{3}}
turunkan kanan kiri

y^{2} =x^{-1}+2x^{-2}+3x^{-3}

2y.y'=(-1)x^{-2}+2(-2)x^{-3}+3(-3)x^{-4}

2y.y'=-x^{-2}-4x^{-3}-9x^{-4}

2y.y'= -\frac{1}{x^{2}} - \frac{4}{x^{3}}- \frac{9}{x^{4}}

y'=  \frac{ -\frac{1}{x^{2}} - \frac{4}{x^{3}}- \frac{9}{x^{4}} }{2y}

y'= \frac{ -\frac{1}{x^{2}} - \frac{4}{x^{3}}- \frac{9}{x^{4}} }{2 \sqrt{ \frac{1}{x}+\frac{2}{x^{2}}+\frac{3}{x^{3}}}}
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