Jawabanmu

Jawaban paling cerdas!
2014-05-20T00:35:21+07:00
Bayangan menara = y- 4\sqrt{3}
bayangan gedung = y

 \frac{y}{y-4 \sqrt{3} } = \frac{62}{50} \\ 25y=31y-124 \sqrt{3} \\ 6y=124 \sqrt{3} \\ y= \frac{62 \sqrt{3} }{3}

tan  \alpha = \frac{ \frac{62 \sqrt{3} }{3} }{62} \\ tan \alpha = \frac{ \sqrt{3}}{3} \\  \alpha =30^0
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