Jawabanmu

2014-01-26T19:35:57+07:00
Himpunan semesta yg mungkin darin ( balok, kubus ) adalah
2014-01-26T20:21:00+07:00
3^(4x+1) – 8. 3^(x-3) = 0
=> (3^x)^4.3 – 8. (3^x).3^(-3) = 0
=>  3.(3^x)^4 – 8/27 (3^x) = 0 , misalkan: y = 3x
=> 3y^4 – 8/27 y = 0 => y (3y^3 – 8/27) = 0 => y=0 (tidak memenuhi) dan
=> 3y^3 – 8/27 =0
=> 3y^3 = (2/3)^3 => y^3 = 3^(-1).(2/3)^3
 => Y = 3^(-1/3).(2/3) => y = 2. 36(-4/3)
Dari pemisalan: y = 3^x Diperoleh: 2.3^(-4/3) = 3^x => log 2. 3^(-4/3) = log 3^x                                                  log 2 + log 3^(-4/3) = x log 3
=> log 2 + (-4/3)log 3 = x log 3
jadi  x = ( log 2 + (-4/3)log 3) = log 2/log 3 – 4/3                                                                                    log 3