Jawabanmu

2014-01-26T18:12:24+07:00
Silinder pejal (I = \frac{1}{2} m.r² )
m = 0,5 kg
r= 12cm => 0,12 m
I = 1/2 x 0,5 x (0,12)²
=3,6x10⁻³
torsi = 3,6x10⁻²
Torsi = I.α
α = torsi÷I
= 3,6x10⁻²÷3,6x10⁻³
= 10 rad/s²
4 4 4