Jawabanmu

2014-01-25T22:25:29+07:00
[OH-] = √ Kb x M basa = √ 4x10^-5 x 0,1 = √ 4 x 10^-6 
pOH = - log [OH-] = - log √ 4 x 10^-6  
Jawaban paling cerdas!
2014-01-25T22:33:49+07:00
OH=(kb.M)^1/2
OH=(4.10^-5.0,1)^1/2
OH=2.10^-3
pOH=3-log2
pH=14-pOH
pH=14-(3-log2)
pH=11+log2

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