Jawabanmu

2014-05-11T22:03:31+07:00
[H2S04] =  10^{-8}
pH = -log[ H^{+} ]
     = -log 10^{-8}
     = 8
1 5 1
2014-05-11T22:08:46+07:00
[H+]= a×M = 2×10^-8 = 2×10^-8
jadi, pH= 8-log 2
oh iya sih bener, lupa kalo rumusnya M x a
iya