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2014-05-11T23:04:54+07:00
SinB = -12/13
alas = √((13)² - (12)²)
       = √(169 - 144)
       = √25
       = 5
karena yang diminta ada di kuadran III, maka alas = -5 selanjutnya
Cos B = -5/13
Tan B = -12/-5 = 12/5
C0t B = -5/-12 = 5/12
Sec B = 1/CosB = 1/(-5/13) = -13/5
Csc B = 1/Sinx = 1/(-12/13) = -13/12