Jawabanmu

2014-01-24T23:44:15+07:00
Rumus asam kuat [H+]= jml H x M
1. [H+]= 1 x 0,02= 0.02
2. [H+]= 2 x 0.3= 0.6
3. asam lemah:  \sqrt{ka.M
[H+]=  \sqrt{10^{-5}.4.10 ^{-3}  }
= \sqrt{4.10 ^{-8} }
=2. 10^{-4}
2014-01-24T23:51:06+07:00

[H+] = a. M

1. HCl--> H+  + Cl- a=2
[H+]= 1. 0,02=0,02M

2.H2SO4--> 2H+  + SO4 2-  a=3
[H+]= 2. 0,3=0,6M

3. CH3COOH--> CH3COO- + H+
[H+]= √ka.M = √10^-5 X 4.10^-3= 2.10 pangkat -4