Jawabanmu

Jawaban paling cerdas!
2014-05-11T11:04:19+07:00
Mol CH _{3}COOH = 0,1M . 50 ml = 5mmol
Mol CH _{3}COONa = 0,2M . 50 ml = 10mmol

 H^{+} = Ka .  \frac{mol asam}{mol garam}

 H^{+} =  10^{-5} .  \frac{5}{10}

 H^{+} = 5.10 ^{-6}

Jadi PH = 6-log5
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