Jawabanmu

2014-05-09T20:33:17+07:00
F(x)=6*x^(-2)*x^(1/2)
f(x)=6*x^(-3/2)
f ' (x)=6*(-3/2)*x^((-3/2)-(2/2))= (-9)*x^(-5/2)
di pg adanya -9 akar x/x^3 dan -9 akar x /x.