Jawabanmu

2014-05-07T20:04:24+07:00
Q= m.c.delta t
42000= 0,2 × 4200 (t2 - 25)
4200/0,2 = 4200 (t2 - 25)
2100 = 4200t2 - 105000
126000 = 4200 t2
t2 = 126000/4200 = 30 derajat celcius
2014-05-07T20:24:59+07:00
42000=0,2x4200(t2-25)
42000=840(t2-25)
t2-25= 42000÷840=50
t2= 50+25= 75
jdikn yg terbaik ya :)