Jawabanmu

2014-05-07T14:11:01+07:00
Ksp CaCo3 =4,8 x 10-9 berapa kelarutan caco3 dalam air
CaCO3 --> Ca^+2 + CO3^-2
Ksp = 4,8 x 10^-9
Ksp = [
Ca^+2][CO3^-2]
4,8 x 10^-9 = s x s
s^2 = 4,8 x 10^-9 = 48 x 10^-10
s = akar(48 x 10^-10) = (4x10^-5) akar3 = 6,9 x 10^-5
Jadi, kelarutan CaCO3 dalam air adalah (4x10^-5) akar3 = 6,9 x 10^-5