Jawabanmu

2014-05-06T21:29:50+07:00
PH = 13 --> pOH = 1 --> [OH^-] = 10^-1 Stelah ditambah air, pH = 12 --> pOH = 2 --> [OH^-] = 10^-2 V1M1 = VcMc V1.10^-1 = (V1+Vair).10^-2 0,1V1 = 0,01V1 + 0,01Vair 0,01Vair = (0,1-0,01)V1 = 0,09V1 Vair = 9V1 Jadi, volume air yg diperlukan sebanyak 9 volume NaOH