Jawabanmu

2014-05-06T21:09:14+07:00
Konsentrasi [H+] dlm H2SO4= [a] x val asam
                                          = 5.10^-6. 2
                                          = 10^ -5
pH= -log[H+]
krn pH H2SO4=pH (NH4)2SO4, maka [H+] (NH4)2SO4= [H+] H2SO4
[H+]= Vkw/kb x [garam] x val garam
10^-5= V10^-14/10^-5 x [garam] x 2
10^-10= 2.10^-9 x [garam]
[garam]= 5.10^-2

M=gram/Mr x 1000/ml
5.10^-2= gram/132 x 1000/500
gram = 3,3 gr



2014-05-06T21:12:19+07:00
Konsentrasi [H+] dlm H2SO4= [a] x val asam
                                          = 5.10^-6. 2
                                          = 10^ -5
pH= -log[H+]
krn pH H2SO4=pH (NH4)2SO4, maka [H+] (NH4)2SO4= [H+] H2SO4
[H+]= Vkw/kb x [garam] x val garam
10^-5= V10^-14/10^-5 x [garam] x 2
10^-10= 2.10^-9 x [garam]
[garam]= 5.10^-2

M=gram/Mr x 1000/ml
5.10^-2= gram/132 x 1000/500
gram = 3,3 gr <--

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