Jawabanmu

2014-05-04T21:37:14+07:00

pH = 0.5(14 - pKb - log [NH4^+]) 

pH = 0.5(14 + log (Kw/Kh) - log [NH4^+]) 

pH = 0.5(14 + log (10^-14/10^-9) - log [0.01]) 

pH = 5.5 <--

Semoga membantu :)