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2014-05-04T16:06:42+07:00
Diket :n = 5 mol
Vawal = V1 = 20 cm^3
Vakhir = V2 = 50 cm^3R = 8,31 J/mol
T = (27+273) = 300K

Jwb :
W = nRT ln V2/V1 
    = 5 x 8,31 x 300 x ln 20/50   <--
2 5 2
2014-05-04T18:18:00+07:00
N = 5 mol
Vawal = V1 = 20 cm^3
Vakhir = V2 = 50 cm^3R = 8,31 J/mol
T = (27+273) = 300K

W = nRT ln V2/V1  
    = 5 x 8,31 x 300 x ln 20/50