Jawabanmu

2014-05-04T09:39:11+07:00
Y=4X³+2X²-36X+50
Y'=12X²+4X-36
titik belok -> Y'=0
0=12X²+4X-36
0=3X²+X-9

X= \frac{-b+/-  \sqrt{b^{2} - 4ac } }{2a}
X= \frac{-1+/- \sqrt{1^{2} - 4.3.(-9) } }{2.3}

√109=10,..≈10

X1= -11/6 ∨ X2=9/6

X1⇒Y=4(-11/6)³+2(-11/6)²-36(-11/6)+50 =...
X2⇒Y=4(9/6)³+2(9/6)²-36(9/6)+50=... (ini nilai maksnya)

hitungsendiri ya