Jawabanmu

2014-05-03T21:11:34+07:00

CH3COOH (aq) + NaOH (aq) -->CH3COONa + H2O 

(perbandingan koef) 
n CH3COOH= 100ml x 0,1 =10 - (x/40)mmol. Karena asam lemah harus sisa. 
n NaOH = x/40 
n CH3COONa=x/40 

CH3COOH dan CH3COONa membentuk bufer 
maka: 
H+ = Ka x A/G 
10^-5 = 10^-5 x (10-x/40) / (x-40) 
x=200mg <--

Semoga membantu :)