Jawabanmu

2014-05-03T09:17:20+07:00
Diagonal bidang = √4²+2² = √16+4 = √20 = 2√5
diagonal ruang = √4²+3²+2² = √16+9+4 = √29
L = 3*2√5 = 6√5
panjangnya itu 4 cm, lebar 3 , tinggi 2
2014-05-03T09:41:50+07:00
Luas BDHF = 5 x 2 = 10
diagonal bidang alas = 5 (pakai teorema pytagoras)
diagonal sisi samping = akar 13
diagonal sisi depan = 2 akar 5
diagonal ruang = akar 29
diagonal bidang gak 5 akar 2?
asalnya 4 kuadrat + 2 kuadrat = 20
jd panjangnya akar 20 = akar 4 x akar 5= 2 akar 5
kalo setau gue sih diagonal bidang tuh akar 2 kalo diagonal ruang akar 3