Jawabanmu

2014-05-01T16:20:30+07:00
Y= cos((1- x²)/(4+x))
y' = -Sin((1- x²)/(4+x)){-2x(4+x) - (1-x²)}/(4+x)²
   = - {{-2x(4+x) - (1-x²)}/(4+x)²}Sin(1- x²)/(4+x)
   = (2x(4+x) + (1-x²))Sin{(1- x²)/(4+x)}
           (4+x)²
   = (8x + 2x² + 1 - x²)Sin{(1- x²)/(4+x)}
                   (4+x)²
= (x² + 8x + 1 )Sin{(1- x²)/(4+x)}
       (4+x)²