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2014-04-28T18:40:10+07:00
Q = 12 KJ = 12000 Joule
m = 2500 gr = 2,5 kg 
T1 = 30 °C
C(logam) = 0,2 kal/gr °C = 0,2 x 4200 Joule/kg °C = 840 joule/kg °C

T2 =...? 
Q = m c ΔT 12000 = (2,5) (840) ΔT
ΔT = 12000/2100 = 5,71 °C
T2 = T + ΔT1 = 30 + 5,71
    = 35,71 °C

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