Jawabanmu

2014-04-27T19:54:03+07:00
K2CrO4 = 0
(+1 X 2) + BO.Cr + (-2 x 4) = 0
+2 + BO.Cr -8 = 0
+2 + BO.Cr = 8
BO. Cr = 8-2
BO.Cr = 6

K2CrO7
(+1 x 2) + BO.Cr + (-2 x 7) = 0
+2 + BO.Cr - 14 = 0
BO.Cr = 14-2
BO,Cr = 12