Jawabanmu

2014-04-26T16:20:58+07:00
PH awal = pH HCl (karena blm ditambah NH4OH) = 1
pH akhir=
            HCL +   NH4OH -> NH4Cl +  H20
mula:   10 mmol 10 mmol
reaksi: 10 mmol 10 mmol   10 mmol
stmbg:     -              -         10 mmol

M NH4Cl = n/V = 10 mmol/ 200 mL = 0.05
[H+] = akar (Kw/Kb x M)
       = akar (10^-14/10^-5 x 0.05)
       = akar (10^-9 x 0.05)
       = akar (10^-10 x 0.5)
       = 10^-5 x 0.7
pH = 5 - log 0.7
     = 6 - log 7
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