Jawabanmu

2014-04-17T09:14:04+07:00
N O₂ = gr/Mr = 32/32= 1 mol
n CO₂ = gr/Mr = 22/44 = 0,5 mol
 \frac{n1}{v1} =  \frac{n2}{v2} 
     \\  \frac{1}{20} =  \frac{0,5}{x}
x = 10 liter
jd volume CO₂ 10 liter