Jawabanmu

2014-04-12T20:52:16+07:00
 \frac{ \sqrt{2x + 2}-  \sqrt{x+3}  }{ x^{2} - 1}  ×  \frac{ \sqrt{2x+2} +  \sqrt{x+3}  }{ \sqrt{2x+2} +  \sqrt{x+3}  }
           x-3
= ---------------------
 x^{2} ( \sqrt{2x+2} +  \sqrt{x+3} ) -  \sqrt{2x+2} -  \sqrt{x+3}
= 1-3
---------------------------   = -2 / 0 = ~
makasih yah kak. hasilnya tak hingga kan??
iya . insyaallah benar
hasilnya 1/8 loh
2014-04-12T20:56:59+07:00
= {2/2akar[2x+2] - 1/2akar[x+3]}/2x = {2/4- 1/4}/2 = {1/4}/2 = 1/8 cmiiw sorry berantakan