Jawabanmu

Jawaban paling cerdas!
2014-04-11T20:06:40+07:00
Rusuk = 8 cm
jarak M ke AG dimisalkan MP
AG = diagonal ruang = rusuk .  \sqrt{3} = 8 \sqrt{3}

 MA^{2} =  AR^{2} +  MR^{2} (dimana titik tengah AD dimisalkan dgn R)
 MA^{2} =  4^{2} +  8^{2}
 MA^{2} = 16 + 64 = 80 => MA = 4 \sqrt{5}

MG = MA = 4 \sqrt{5}

gunakan rumus perbandingan
1/2 a.t = 1/2 a.t
1/2 MA.MG = 1/2 AG MP
4 \sqrt{5} . 4 \sqrt{5} = 8 \sqrt{3} . MP
MP = 80/(8 \sqrt{3} )
MP =  \frac{10 \sqrt{3} }{3}

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