Jawabanmu

2014-04-10T20:42:52+07:00
Jawab No.3

y = x³+5 → y’ = 3x² 
x+3y = 2 → 3y = -x+2 → y = -(1/3)x+(2/3) 
m1 = -1/3 
tegak lurus → m2 = -1/m1 = -1/(-1/3) = 3 
m2 = y’ → 3 = 3x² 
x² = 1 → x = 1 
x=1 → y = 1³+5 = 6 
titik singgung (1,6) 
y – y1 = m2(x – x1) 
y – 6 = 3(x – 1) 
y = 3x + 3

2 5 2