Jawabanmu

2014-04-09T20:41:10+07:00
CH3COONa
OH- =  \sqrt{ \frac{kw}{ka}.[G]
\sqrt{ \frac{ 10^{-14} }{ 1.7.10^{-5} }.[ 10^{-2} ]
 \sqrt{0.6 .   10^{-11}
=0.7 . 10^{-5.5}
pOH = -log OH-
= -log 0.7.  10^{-5.5}
= 5.5 -log 0.7
pH = 14 - (5.5 -log 0.7)
= 8.5 + log 0.7