Jawabanmu

2014-04-09T14:49:16+07:00
Y = 3x  \sqrt{2x+7}
y = 3x ( 2x+7 ) ^ \frac{1}{2}
y' =  \frac{1}{2} 3 2 ( 2x+7 )^ \frac{1}{2}
y' = 3 ( 2x+7 )^-  \frac{1}{2}
y' = \frac{3}{ \sqrt{2x+ 7} }