One kilogram of ice has a temperature of -2 derajat C.if the melting point of ice = 0 derajat C,the specific heat of ice = 0,5 cal/g derajat C, the specific heat of water = 1 cal/g , and 1 calorie = 4.2 J. the heat required to completely melt the ice is...

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Jawabanmu

2014-04-08T20:11:53+07:00
Qab=mxcxdelta T =1x0,5x2 =1kal.=4.200J Qbc=mxL =1x336.000 =336.000 Qabc=Qab+Qbc =4.200+336.000 =340.600J