Jawabanmu

2014-04-08T19:21:26+07:00
PH = 10
pOH = 4
[OH-] = 10^-4

Mg(OH02 <==> Mg^2+ + 2 OH-
. . .s . . . . . . . . .s . . . . . . .2s

2s = 10^-4
s = 5 10^-5

Ksp = (s)(2s)^2 = 4s^3
Ksp = 4 (5 10^-5)^3 = 5 x 10^-13
1 5 1
2014-04-08T19:28:58+07:00
PH = 10
pOH = 14 - 10 = 4
[OH] = 10^⁻4

Mg(OH) => Mg^2 + 2OH
                 0,5       10^⁻4
Ksp Mg(OH) = [Mg^2]  [OH]^2
                   = 0,5 x 10^⁻4 (10^⁻4)^2
                   =5 x 10^ ⁻13

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