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2014-04-08T15:03:06+07:00
CH3COONa + H2O >< (reaksi bolak balik) CH3COOH + NaOH Kh = 1x10^-14/4,8x10^-7 = 2,1x10^-8
2014-04-08T17:05:29+07:00
Kh=kw/ka
kh=10^-14 / 4,8 . 10^-7
kh= 0,2 . 10^--7

kh=tetapan hidroliss
kw=tetapan ksetimbangan air
ka=tetapan ionisasi asam lemahh
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