suatu persegi panjang mempunyai panjang (8x+6)cm dan lebarnya (10x-27) cm . bila kelilingnya102 cm, berapa panjang dan lebarnya

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kll prsgi pjg : 2(p+l) ... 102 = 2(8x+6)+ (10x-27) .... 102= 2(18x-21) ...... 102= 32x-42.....102+42=32x............. 144=32x/.............x=144/32=

Jawabanmu

2014-04-04T08:56:41+07:00
2((8x + 6) + (10x - 27)) = 102
<br />
2(18x - 21) = 102
<br />
36x - 42 = 102
<br />
36x - 42 + 42 = 102 + 42
<br />
36x = 144
<br />
36x/36 = 144/36
<br />
x = 4
<br /><br />
Panjang = (8x + 6) = (8(4) + 6) = (32 + 6) = 38 cm
<br />
Lebar = (10x - 27) = (10(4) - 27) = (40 - 27) = 13 cm
<br /><br />
Semoga membantu..
2((8x + 6) + (10x - 27)) = 102
2(18x - 21) = 102
36x - 42 = 102
36x - 42 + 42 = 102 + 42
36x = 144
36x/36 = 144/36
x = 4

Panjang = (8x + 6) = (8(4) + 6) = (32 + 6) = 38 cm
Lebar = (10x - 27) = (10(4) - 27) = (40 - 27) = 13 cm

Semoga membantu..
terimakasih banyak
Sama" :)
Jadikan terbaik & Terima Kasih yaa.. :)
2014-04-04T08:56:51+07:00
K = 2p + 2 l
2p + 2l = 102
2(8x + 6) + 2 (10x - 27) = 102
⇔16x + 12 + 20x - 54 = 102
⇔36x = 102 + 54 - 12
⇔36x = 156 - 12
⇔36x = 144
⇔x = 144/36
⇔x = 4
jadi Panjang = 8.4 +6 = 38 cm
lebar = 10.4 -27 = 13 cm
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