Jawabanmu

2014-01-17T17:09:36+07:00
PH asam lemah 5
maka [H+] = 10^-5.................. ^ dibaca pangkat
Rumus asam lemah
[H+] = akar (Ka x Ma)
10^-5 = akar (10^-4 x Ma)
10^-10 = 10^-4 x Ma
Ma = 10^-10 / 10^-4 = 10^ -6

semoga bermanfaat :)
2014-01-17T18:34:03+07:00
PH=5
maka H+ = 1 x 10^-5

H+ = Akar Ka x M
1 x 10^-5 = Akar 10^-4 x M
1 x (10^-5)^2 = 10^-4M
M = 1 x 10^-10/1 x 10^-3
M = 1 x 10^-7 M