Jawabanmu

2014-04-02T11:47:58+07:00
Y₁=x²-4x+3
y₂=-x+3
x²-4x+3=-x+3
x²-3x=0
x(x-3)= 0
x= 0 dan x = 3
L= integral x²-3x batasnya 0 dan 3
  = (1/3 x³ - 3/2 x²)
  = (1/3 3. 9 - 3/2 9)-(1/3 0 - 3/2 0)
  = 9- 27/2- 0
  =(18-27)/2 = -9/2 = -4 1/2 (tanda min dihilangkan) jawabannya yg A