Jawabanmu

2014-03-30T16:10:16+07:00
F (x)=x^2-2x+1....f'(x)=2x-2....f'(4)=2 (4)-2=6
eh itu f^-1 ya
f^-1 (x)=akar (x)+1....f^-1 (4)=akar (4)+1=3
2014-03-30T16:19:20+07:00
f^-1 (x)=akar (x)+1....f^-1 (4)=akar (4)+1=3
f(x)= x^2 - 2x + 1
f(x)= x^2 - 2x + 1
f^-1(x) = y
x^2 - 2x + 1= y
x^2 - 2 = y + 1