Jawabanmu

2014-03-28T17:31:03+07:00
 integral dari x = -1 sampai x = 1 
V = π ∫ y² dx = π ∫ (x² - 1)² dx 
= π ∫ (x⁴ - 2x² + 1) dx 
………………………….1 
= π[(1/5)x⁵ - (2/3)x³ + x] 
…………………………-1 
= π[(1/5)1⁵ - (2/3)1³ + 1 – ((1/5)(-1)⁵ - (2/3)(-1)³ + (-1))] 
= π[(1/5) - (2/3) + 1 – (-(1/5) + (2/3) -1)] 
= π[(1/5) - (2/3) + 1 + (1/5) - (2/3) +1)] 
= π[2/5 – 4/3 + 2] 
= π[6/15 – 20/15 + 30/15] 
= (16/15)π satuan volume