Mohon Bantuannya dan Penjelasannya :)

1. jika diket Matriks A=0 -1 B= 2 1 , Maka Determinan dari (A ͭ +B) ² ?
4 -2 4 5

2. Jika A= 5 2 B= 0 3 C=5 0 , Jika D= (2A+C ͭ ) - 3A ͭ +4B ?
6 4 4 6 -1 4

3. C= 2 3 3 6 D= 4 0 0 0 ,Hitung Determinan CD....
0 5 5 7 2 4 0 0
0 0 3 4 0 1 3 4
0 0 0 5 0 2 2 5

Terimakasih :)





1

Jawabanmu

2014-03-28T00:40:44+07:00
1. A^{t} =   \left[\begin{array}{ccc}0&4\\-1&2\end{array}\right],    A^{t} + B = \left[\begin{array}{ccc}2&5\\3&3\end{array}\right], (A^{t} + B} ){2}  = \left[\begin{array}{ccc}19&25\\15&24\end{array}\right]

Det(A^{t}+B)^{2} 19.24 -15.25 = 81

2.A^{t} =   \left[\begin{array}{ccc}5&6\\2&4\end{array}\right] , C^{t} = \left[\begin{array}{ccc}5&-1\\0&4\end{array}\right] \\ D= 2\left[\begin{array}{ccc}5&2\\6&4\end{array}\right] +   \left[\begin{array}{ccc}5&-1\\0&4\end{array}\right] - 3  \left[\begin{array}{ccc}5&6\\2&4\end{array}\right] + 4 \left[\begin{array}{ccc}0&3\\4&6\end{array}\right] =  \left[\begin{array}{ccc}0&-3\\22&24\end{array}\right]

3 Det (CD) = Det(C).Det(D) [karna C dan D bujursangkar]
Det (C) = 150 [ perkalian diagonal, karna segitiga bawah]
Det (D) = 122 [-,-]

Det(CD) = 150.122 = 18.300
makasih makasihh :) :) tp masih bingung akunya hehe
males banget buat jawaban matriks kayak gini hadeuh -_-