Jawabanmu

2014-01-16T07:50:22+07:00
ΔTf = Tf pelarut-Tf larutan glukosa
      = 0 -(-0,18) = 0,18°C
ΔTf glukosa= Kf x m
  0,18 = Kf x 0,1
Kf = 0,18 : 0,1= 1,8

CaCl2 ---> Ca²⁺ + 2Cl⁻  sehingga i=1+2=3
ΔTf= Kf x m x i
      = 1,8 x 0,2 x 3
      = 1,08°C
ΔTf = Tf pelarut-Tf larutan CaCl2
1,08°C = 0°C - Tf larutan CaCl2
Tf larutan CaCl2 = -1,08°C