Jawabanmu

2014-03-27T05:45:02+07:00
Diketahui:
Q = 67.200 J = 67,2 × 10³
C air = 4,2 × 10³
m = (800 gr ÷ 100) = 8 kg
t1 = 30 derajat

Ditanya: t2 = ....?

Jawab:
Q = m.c.ΔT
67,2 × 10³ = 8 × 4,2 × 10³ × ΔT
67,2 × 10³ = 33,6 × 10³ × ΔT
ΔT = 67,2 × 10³
        33,6 × 10³
     = 2

t2 = ΔT + t1
    = 2 + 30
    = 32 derajat


Maaf kalau salah
2014-03-27T08:58:38+07:00
Delta T=Q/mxc =67200/0,8x4200 =67200/3360 =20°C jadi suhu akhir=30+20=50°C