Jawabanmu

2014-03-26T21:53:16+07:00
A. Mol naoh = 8/39 =0.2 mol [Naoh]= 0.2x20=4 molar [oh]=4 poh= -log 4=-2log2=1 ph=14-1=13
b.n ch3cooh = 0.1 mol [ch3cooh]=0.1x0.5=0.05. [h]=akar kaxma=akar 1.8x10-5x5x10-2=18x5x10-8=90x10-8diakar= 9x10-7 diakar= 3x10-3.5  ph= 3.5-log3 

Nomer c nyusul bentaar
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