Jawabanmu

Jawaban paling cerdas!
2014-03-26T20:10:50+07:00
jarak bidang BCHE dan PQRS = jarak A' - A", dimana A' pertengahan SR dan A" pertengahan BE

 \frac{A'A"}{AA"} =  \frac{SB}{AB}   \\ A'A" = \frac{SB}{AB}AA" \\ A'A" = \frac{a/2}{a} \frac{ a\sqrt{2}  }{2} =  a \frac{ \sqrt{2} }{4}
1 5 1