Jawabanmu

2014-03-26T00:10:06+07:00
Q=mCΔt
Q=2,7kgx460J/kg'Cx(80-20)'C
Q= 2,7x460Jx60
Q= 74.520 J
2014-03-26T03:58:29+07:00
Q= m.c.delta T m: 2,7 kg c : 460 j/kg °C delta t: suhu akhir-suhu awal : 80°-20° :60° = 2,7 x 460 x 60 = 74.520 J