Jawabanmu

2014-03-26T00:04:52+07:00
Kelarutan = s
Ca(OH) ⇒Ca²⁺+2OH⁻
                s      (2s)²
Ksp= 4s³
s= ∛(Ksp x 1/4)
s=∛(5x10⁻⁶x1/4)
s=∛500x10⁻⁸x1/4
s=∛125x10⁻⁸
s=5x10⁻³∛10

Ph jenuh berarti larutan tepat jenuh Q=Ksp
Ca(OH) ⇒Ca²⁺+2OH⁻
5x10⁻⁶     5x10⁻⁶ 10x10⁻⁶
[OH]⁻=10⁻⁵
POH= -log [OH]⁻
POH= -log10⁻⁵
POH=5
PH=14-5
PH=9
5 1 5