Jawabanmu

2014-03-25T22:39:55+07:00
A. keliling ABCD = AB + BC +CD + AD = 17+17+10+10 =54 cm
b. luas ABCD = 1/2 d1.d2 = 1/2 . 16 . 21 = 168 cm2
2014-03-25T22:44:13+07:00
A. Keliling = 2×10 + 2×17 = 54cm

B. O titik tengah layang2, AD = 10 AO=8 maka DO = 6 (triple phytagoras)
AB = 17, AO = 8, maka OB = 15,
d1=16, d2=21
L= \frac{16.21}{2}= 168 cm²