Jika f(1/2x) = x²/x-1 , maka f (x) =
jika f(2x+6) =4x²+2x , maka f (x) =
jika f(x+3) = 2x+1 , maka f (x) =
jika f(ax) = 2x +1 dan f(1) = 5 , maka f (2) =

tolong bantu yaa temaann :( pleasee banget
semampu kalian, kalo bisa semuaa terjawab. thank

1
sori ini yg poin a f(1/2x) atau f(x/2) ?
f(1/2x) atau bisa dibilang setengah x gan. tolong bantu yaaa ;)

Jawabanmu

2014-01-15T17:05:31+07:00
jika f(1/2x) = x²/x-1 ,

y =
(1/2)x
x = 2y


maka f (x) = (2x)² / 2x-1
f(x) = 4x
² / 2x-1
---------------------------------------------------------------------------------
jika f(2x+6) =4x²+2x

y = 2x + 6
2x = y - 6
x = y/2 - 3

maka f(x) = 4 (x/2 - 3)
² + 2(x/2 - 3)
f(x) = 4 (x
²/4 - 3x + 9) + x - 6
f(x) =
x² - 11x +30
-----------------------------------------------------------------------------------
jika f(x+3) = 2x+1

y = x+3
x = y-3

maka f(x) = 2(x-3) + 1
f(x) = 2x - 5
-----------------------------------------------------------------------------------
jika f(ax) = 2x +1 dan f(1) = 5 , maka f (2) =

y = ax
x = y/a

f(1) = 2(x/a) + 1 = 5
2(x/a) = 4
x/a = 2
a = x/2

y = ax
y = (x/2)x
y = x²/2
x² = 2y
x =
+-

yap, jadi jawabannya ada 2 nih :
jika x = -
f(x) = -2
+ 1
f(2) = -2(2) + 1
f(2) = -3

jika x = +
f(x) =
2 + 1
f(2) = 2(2) + 1
f(2) = 5

semoga membantu :)
Makasih banyak yaa gan, sangat membantu ;) salam kenal
iya.. salam kenal juga ;)